I have a fitted and a spare, hand-wheels for my ML7's 8TPI lead-screw, although to be honest I don't use it very often.
'
Wheel 1
Graduated 0 = 125 in 10s then 5.
One revolution moves the carriage 1/8" = 0.125".
So one minor graduation = 0.125 / 125 = 0.001.
So far so good. The engraving is even deep enough to be filled for contrast.
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Wheel 2
(That presently fitted) 0 = 160, all in 10s.
I've not right good at sums but trying to work out what those are supposed to be, gives strange answers.
I thought first, "direct" equivalents for binary fractions. 20 on the scale gives 1/64", but still demands quite a lot of arithmetic for such use. For that I'd rather have a scale divided into just 8, numbered by the vulgar fractions, not tens.
Using the same arithmetic:
0.125 / 160 = 0.000781
Eh?
A thought….
Does anyone know the lead on a metric Myford lathe? The nearest to 1/8" is 3mm but 3mm / 160 gives 0.019mm per minor division. ( 0.02mm steps would need 150 divisions.)
So meaningless for 3mm lead, but 4mm lead gives one mark = 0.025mm.
So is this hand-wheel really for a metric lead-screw of 4mm lead?
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Why two wheels, one with strange graduations?
I had bought a hand-wheel only to find some while later, that it would not fit as the driving slot was too far off-centre; so I failed to spot this strange scale The kind lady on the Myford stand at one of the shows replaced it with the true Imperial-scale one, but didn't keep the faulty one.
Subsequently, when fitting a screw-cutting gearbox, I made a new lead-screw, from ACME bar-stock, to preserve the original screw lest it is needed again. I gave the new screw a slightly over-size metric roll-pin for the hand-wheel: lots in stock, and I could enlarge and partially centre the faulty hand-wheel's off-centre slot to suit.
The other would need the pin changing.