I am struggling with bevel gear calculations for the od of the pinion ( and wheel). It’s the first gears I have cut for over 50 years and to coin an expression. “ it’s doing my ed in”. Perhaps those with superior knowledge can help here I’m showing the calcs for the pinion, when the problem is found here all should be easy to follow up for the wheel the cutters are made to clicksring’s “tools glorious tools” utube A long but interesting task!
It’s for a governor of 32 dp with 16 and 32 teeth.
Inner pitch dia. = n/dp = 16/ 32 = 0.5
Slope angles are ( pinion ) 26.34. And (wheel) 64.26 degrees
For reference I am using Lammas data from ME Oct 1991 p 447 and Laws book p 106
Using each of these I get an od for the pinion of. 0.696 (Law) 0.756 (Lammas). Which is correct!
Law is not fully clear about his calculations for the large end dia., it took a while for me to realise the last number in his calculations is in fact the difference between the PCD and the od of the small end. That is the addendum x 2 and that he uses the cone length in the first expression.
Addendum is thus 1/dp x sin26.34 x 2. Or .0.0312 x0.4436 x2. = 0.0137 (on single tooth), 0.027 on diameter
Inner cone length is the same to both authors at 0.563 and face length of 1/3 = .0.75 total
This gives me
(Law)…..[(cone length)x sin26.34×2 ] + addendum. = (.75 x .4436 x 2)+ .027 = 0.696
Lammas does it differently using outer pitch dia. ( 1.4 x ipd ) = 0.7. So
Od= opd + (2 x cos 63.24 / dp) = 0.7 + (2x .896 / 32) = 0.756
Now that’s a big difference for such a small gear. Both should be the same Help would be appreciated