OK, something a little different for a Friday evening…
I've been reading here about capping beer bottles using a pneumatic cylinder…
pneumatic beer bottle capper
To give you an idea of the kind of thing being used to do this…

It is stated that the force required is "314 pounds" (100 PSI acting on a 2" bore cylinder). I'll take this as being 142kgf, or ~1400N.
All well and good, but I have no experience with pneumatics and no air compressor. I'm wondering if some electro-mechanical contrivance might work?
Consider a stepper motor generating 1Nm of torque (there may be much better motors for this job, but I've only ever played with steppers). A module 1 20 tooth spur gear mounted to this (driving a rack, for example), would generate a force of 100N, as the edge of the gear is 0.01m from the centre (length x force = torque).
This isn't enough, but we can of course use gears to reduce the rpm but increase the torque. A 14:1 gearbox would get us there.
I think the reduction in RPM is ok. The capper does not need to actuate very quickly, and provided the stepper can deliver maximum torque at 60rpm (datasheets I've looked at suggest this is ok) then I think the operation could be completed in a few seconds.
I'm pretty new to this – are there any obvious errors in my thinking above? What I don't have a feel for is whether small module 1 gears can be expected to carry these kinds of forces. Larger gears would be probably result in a solution that was too large (compared to the pneumatic cylinders anyway, which are probably the sensible way of tackling this…). Also, I would guess a 14:1 reduction would need a 2-stage gearbox…
Jed