I am building a stationary steam mill engine. I'm resizing the plans upward to do this. The original cylinder is 1/2" bore x 1". this gives a capacity of 0.196 cu. in. and a surface area of the piston of 0.196 sq. in.
Mine will be 1" bore x 2". this gives a capacity of 1.570 cu. in. the piston will have a surface area of 0.785 sq. in.
The capacity increases x 8, the surface area x 4.
The original flywheel is 3" x 1/2". (3.534 cu. in.)
What size should my flywheel be? Doubling the size the same as all other measurements gives me 28.274 cu. in. or 8 times the volume hence weight. it seems a lot for a small engine to drive.
Edited By Stephen Follows on 25/01/2018 19:31:23