I have a dead LED batten. Opening it up I found that a wire wound resistor had overheated – and gone open circuit. However I cant figure out what resistance it was supposed to be.
It's a 5W(?) series resistor between the incoming 240v mains and the control circuit.
The colour code seems to be Red-Black-Gold-Gold-Black which beats me. Two gold bands seems to have escaped my code charts. As has a black tolerance band. But Black as the first digit also seems wrong!
Can someone with more electronics experience possibly give me an idea of what It might be.
This will be a fusible resistor that forms the function of a fuse.There will be other failed components that have caused this resistor to fail. You will need to identify and replace ALL the components that have failed.
I think the resistor was probably 2 ohms. 20 x first gold multiplier of 0.1. second gold tolerance. I think the end black possibly indicates that it is a fusible resistor.
A wirewound non-precision resistor is unlikely to use four bands to determine value. To me the leftmost band looks brown rather than red. So I take the resistor to be as follows, from the left:
Value: Brown Black Gold – 10×0.1 = 1 ohm
Tolerance: Gold – 5%
The rightmost black band could be temp coefficient, in which case it is 250ppm/K, ie, not very good.
Gold as a multiplier is x 0.1 ohms. Gold as tolerance is 5%. That would make your resistor 2 ohms if it wasn't for the 4th black band. Don't know what that is there for.**LINK**
That site says "If an additional fifth band is black, the resistor is wire wound resistor. If an additional fifth band is white, the resistor is fusible resistor." I had not seen that before.
So it's probably a 1 (or possibly 2) ohm 5% wire wound 5 watt resistor. I can't see any signs of damage elsewhere on the board. I am thinking that the sort of power it would take to blow that resistor would have left some sort of evidence on the rest of the board which is mainly surface mounted IC's and resistors.
I might venture a repair. The unit has been replaced by the supplier under warranty, so it's an academic exercise