Posted by Bevel on 20/05/2023 13:48:47:
Say for instance we take the tube I mentioned, do I need to calculate the whole surface area for outer and inner dia's? Also when doing multiple parts do I say calculate whole area for one then times by number I intend to do in one hit?
Yes and yes
I calculate based on 6mA per square cm which is near as dammit the same as 6A / square foot. I then use a constant current power supply to maintain this. For a protective coating, I find that 1 hour is enough, or 2 hours if the anodising will by dyed. (I think that this is the same basis as the '720' rule with 13µm or 25µm thickness respectively).
I have a simple spreadsheet that I use to calculate simple parts as a combination of blocks, cylinders and discs, but it the part is drawn in CAD, I can get the surface area reported from it.
Note that I quite often require >20 volts to maintain the required current. (This is with sodium bisulphate rather than sulphuric acid, but I don't think that should make any difference – the chemistry is the same.). A warmer bath needs less volts, but I've had rough looking coatings if the bath warms up too much. I don't bother with agitation, but then I'm not chasing any sort of specification.
I clean the parts using fairy liquid and Scotchbrite under running tap water. I avoid them drying out between final cleaning and anodising by keeping them submerged in tap water. They have a quick dip in dilute sodium hydroxide (2% solution for 1-2 minutes – long enough for them to be covered in fine, white bubbles), then a rinse with DI water from a spray bottle, and into the anodising bath. They get another spray rinse when they come out, and I seal in almost boiling tap water for ~20 minutes.
I have been pleasantly surprised by the predictability and consistency of the results. It's a lovely way to tidy up aluminium parts.