Adjusting the horizontal mill

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Adjusting the horizontal mill

This topic has 54 replies, 10 voices, and was last updated 22 April 2023 at 13:24 by Steve355.

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1 January 2022 at 12:12 #577897
Steve355
Participant
@steve355
It was inevitable really that the proper fun and games would start once I had got it back together. Any mill manufactured in 1941, with bearings marked 1939 is going to be a challenge.

I have done some test cuts – not too bad but a little chatter and a “throbbing” noise which indicated (I presume) that something is not quite aligned right. I adjusted the belts which improved it somewhat, but it’s still there.

Putting the dial indicator on the spindle I get 0.001 runout.

on the flange (?) of the spindle, I actually get more runout, about 0.00175

But interestingly, on the spindle near the *rear* bearing I seem to get no perceptible runout…

All this seems to indicate that the front bearing isn’t quite seated correctly, or is not adjusted / malfunctioning.

I suppose the spindle could be bent.

I didn’t manage to get the front bearing off when cleaning up the parts. It was well and truly stuck on the spindle and I didn’t want to bash it and risk damaging it. I don’t really know how to remove it.

Spindle out and reseat the front bearing?

I have read Ketan’s advice on preload and heating, that was interesting but I wasn’t sure it was directly relevant to this.

Thanks

Steve
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1 January 2022 at 12:12 #11069
Steve355
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@steve355
1 January 2022 at 17:43 #577959
Dave Halford
Participant
@davehalford22513
What runout does the arbour show?

The drive pullies will show more than 1 thou runout and the belts won't care.

BTW there are some £25 gear cutters out there that have a lot more run out than that.

When you cleaned the bearing did you spin it dry on the shaft? Damaged ones will catch.

Whats the end float on the shaft?

Edited By Dave Halford on 01/01/2022 17:47:43
1 January 2022 at 17:46 #577961
Steve355
Participant
@steve355
Looks like I fixed it, disassembled, cleaned it all up, put it back together very carefully. Now I’m getting less that 0.0005 runout at the spindle, which is probably surface imperfections.

The mill still makes a throbbing noise though, but the surface finish looks a lot better.

Steve
1 January 2022 at 17:52 #577962
Steve355
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@steve355
Posted by Steve355 on 01/01/2022 17:46:05:

Looks like I fixed it, disassembled, cleaned it all up, put it back together very carefully. Now I’m getting less that 0.0005 runout at the ARBOUR, which is probably surface imperfections.

The mill still makes a throbbing noise though, but the surface finish looks a lot better.

Steve

Corrected!
1 January 2022 at 18:05 #577964
Anonymous
All cutters have some run out. On a horizontal mill the depth of cut is normally far greater than runout so it is not a problem. When I first used my horizontal mill it chattered, and the whole mill shook. Impressive given that it weighs the best part of 2 tons. The cure was simple; double the feedrate so that the cutter teeth were cutting, not rubbing. I use an absolute minimum chip load of 4 thou/tooth.

Andrew
1 January 2022 at 22:00 #577991
Steve355
Participant
@steve355
Posted by Andrew Johnston on 01/01/2022 18:05:34:

All cutters have some run out. On a horizontal mill the depth of cut is normally far greater than runout so it is not a problem. When I first used my horizontal mill it chattered, and the whole mill shook. Impressive given that it weighs the best part of 2 tons. The cure was simple; double the feedrate so that the cutter teeth were cutting, not rubbing. I use an absolute minimum chip load of 4 thou/tooth.

Andrew

I’m struggling a bit with the speeds, feeds and chip load

it has 3 speeds, 250, 500, and 850 rpm

To get a chip load of 0.004 at 250 rpm with say a 12 tooth cutter, apparently I need 10 inches per min. It seems much slower than that. Perhaps I’m not understanding it.
1 January 2022 at 22:27 #577995
Anonymous
Those speeds are quite high for HSS side and face cutters. Let's assume a 3" diameter cutter. A rule of thumb for a HSS cutter in low carbon steel is 100 feet per minute. For a 3" diameter cutter that equates to 106rpm.

Feed rate = chip load x number of teeth x rpm

So for the numbers given, 0.004" chip load, 12 teeth and 250rpm we get a feedrate of 12". That's quite high, my (metric) horizontal only goes to 400mm/min.

Ideally the arbor speeds need to be reduced. I run side and face cutters, and slitting saws, from about 60rpm to 120rpm in steel.

Andrew
1 January 2022 at 23:25 #577999
Bazyle
Participant
@bazyle
Hang on , isn't 400mm/min faster ie about 16in per min.

But as your calculations have shown if you have that many teeth you have to move it fast to keep the 4thou per tooth. Since you don't want to drop below 2 thou per cut to avoid rubbing if it isn't dead concentric you have to move the table at least 6in per min.
Larger mills run slower rpm but that is to enable big cutters to be used, no to slow production down. 250 rpm is about right for a 3in cutter. The only other limitation is the hp of the motor and can it do the work.
2 January 2022 at 07:42 #578018
JasonB
Moderator
@jasonb
Out of interest as this is a small machine what is the arbor diameter? Could be 3/4" on a machine this size so you may be better off coming down to smaller dia cutters then the spindle speed will be closer to what is needed.

Smaller dia cutter would also suit the lower power of the smaller machine

Does make you wonder why it has a lowest speed of 250rpm as that would mean you should be using cutters of about 1.5" dia max if sticking to the 100ft/min rule of thumb.

Edited By JasonB on 02/01/2022 07:51:11
2 January 2022 at 08:27 #578022
Steve355
Participant
@steve355
Posted by JasonB on 02/01/2022 07:42:56:

Out of interest as this is a small machine what is the arbor diameter? Could be 3/4" on a machine this size so you may be better off coming down to smaller dia cutters then the spindle speed will be closer to what is needed.

Smaller dia cutter would also suit the lower power of the smaller machine

Does make you wonder why it has a lowest speed of 250rpm as that would mean you should be using cutters of about 1.5" dia max if sticking to the 100ft/min rule of thumb.

Edited By JasonB on 02/01/2022 07:51:11

The arbor diameter is 1”.

However, it makes more sense on reading the original sales literature. The Burke #4 had a lowest speed of 66rpm. But the motor and entire countershaft assembly is not original. It has obviously been replaced by someone who either couldn’t source suitable parts or didn’t know what they were doing. Originally the mill had a geared motor, I’d bet that ran at a nice low shaft rpm. The current one runs at a typical 1400 rpm or whatever (haven’t measured it yet).

I think I’m going to have to sort this out somehow.
2 January 2022 at 09:12 #578025
Anonymous
Posted by Bazyle on 01/01/2022 23:25:41:

Hang on , isn't 400mm/min faster ie about 16in per min.

Correct. I was simply saying that the maximum feedrate on my mill is 16"/min, so a feed of 12"/min is at the high end of the feedrate range on my mill. For completeness the minimum feedrate on my mill is 0.4"/min.

A spindle speed of 250rpm seems awfully high for a 3" diameter HSS cutter. I'd be running at around 100rpm in low carbon steel, and lower still in cast iron or alloy steels.

As stated, the sales literature slowest speed of 66rpm is more like what I would expect for a horizontal mill. For comparisonj the speed range on my mill is 30rpm to 1200rpm, although it does have a dual speed motor.

Andrew
2 January 2022 at 10:08 #578033
JasonB
Moderator
@jasonb
Yes I did look and see that a No4 had a geared head motor, with the 66rpm low speed and you saying you have 250rpm that would probably mean the gears in the head gave a 4:1 reduction. You will either have to add a countershaft or go the VFD route to get that speed down to something that won't overspeed the cutters.
2 January 2022 at 10:47 #578048
Clive Foster
Participant
@clivefoster55965
+1 for what Jason says about re-engineering the countershaft.

Time to hunt down the poly-vee / multigroove belt and pulley catalogues to get something compact sorted out. Rule of thumb with polly-vee is that pulley OD can be less than half the diameter of vee belt ones for same power transmission. Multigroove pulleys are much easier to make than Vee too. Just need to sort out a decent bed stop system on the lathe to get the groove spacing right. A lump bolted to the bed and a set of spacers works fine.

If space is limited I'm rather partial to the "back belt" system that mimics the operating principles of a lathe back gear. Two identical large and small pulley pairs. One pair bolted together running on a countershaft. The other pair has one free running and one fixed to the drive input shaft. Free running pulley has the output pulley bolted to it. If the motor has an adequately long shaft you can do a right neat job by fixing a sleeve to the motor shaft to carry the three concentric pulley set viz fixed input drive and free running output pair. For low powers, 1 hp range, the official belt sizes look stupid skinny!
2 January 2022 at 11:14 #578058
Steve355
Participant
@steve355
Tbh I am tempted by the VFD route! I have put a lot of work into this machine and I want to use it, starting a new countershaft project wasn’t on my list But I will have a think about it, as you say there may be an back gear type solution.

😢
2 January 2022 at 12:08 #578073
Steve355
Participant
@steve355
I just measured the auto-feed rate at 250 rpm – 3 inches per minute. So at 66 rpm it would be unbelievably slow. Something doesn’t seem right….
2 January 2022 at 12:24 #578076
JasonB
Moderator
@jasonb
Was that with the feed pullies in their slowest setting?

I's only slow if using a cutter with lots of teeth, I'm sure Andrew will post a pic of a single point cutter that would be feed at 1"/min to give 0.004" chip load.

Edited By JasonB on 02/01/2022 12:26:40
2 January 2022 at 12:31 #578078
Steve355
Participant
@steve355
Posted by JasonB on 02/01/2022 12:24:20:

Was that with the feed pullies in their slowest setting?

Yes.

I need to understand this calculation!
2 January 2022 at 14:20 #578099
Anonymous
Home made flycutter with single point HSS toolbit, 8.6" diameter, running at 54rpm in cast iron:

Roughing cuts were 50 thou deep and 15 thou per rev feed. For the finishing cut I slowed the feed to 4 thou per rev. Took ages as 0.004" per rev at 54rpm is 0.216"/min. Made worse as I was feeding in Y which means it was by hand – power feed on X only. Made slightly easier as the mill is metric, and since 0.004" is about 0.1mm it was one big division on the dial per clonk.

Andrew
2 January 2022 at 14:34 #578100
Bazyle
Participant
@bazyle
Calculations
Speed of tooth through metal = RPM x pi x diameter.
If the diameter is in inches your speed is of course in inches so by convention measure it in feet.
The number of teeth doesn't matter for this bit. target for mild steel is somewhere between 100 and 200 ft/min. Us amateurs will be in less of a hurry than the professionals and you might want to have flood coolant for the higher rates.

Movement of the table is a separate consideration from the above, which can seem odd but it is.
Here number of teeth matter, but diameter doesn't.
So RPM x No of teeth gives you the number of cuts per minute.
Each cut is say 4 thou but we want to work in inches or feet – so 0.004 in.
That gives you RPM x Teeth x cut which is the feed speed in inches/minute you need to move at to compare with the rates your mill feed provides.

If you are winding the handle manually you probably wan to convert it to inches per second so divide by 60, then multiply by the tpi of your leadscrew. Then you really get a feel of how fast it is and remember if you wobble in your turning you will get grabs or rubbing.

All this can be applied to vertical cutters too and remember not to climb mill on an old machine.

(now I'm off to find the manuals for my machine as I'm not sure I've been going as quick as I should)
2 January 2022 at 14:59 #578105
Steve355
Participant
@steve355
Posted by Bazyle on 02/01/2022 14:34:15:

Calculations
Speed of tooth through metal = RPM x pi x diameter.
If the diameter is in inches your speed is of course in inches so by convention measure it in feet.
The number of teeth doesn't matter for this bit. target for mild steel is somewhere between 100 and 200 ft/min. Us amateurs will be in less of a hurry than the professionals and you might want to have flood coolant for the higher rates.

Movement of the table is a separate consideration from the above, which can seem odd but it is.
Here number of teeth matter, but diameter doesn't.
So RPM x No of teeth gives you the number of cuts per minute.
Each cut is say 4 thou but we want to work in inches or feet – so 0.004 in.
That gives you RPM x Teeth x cut which is the feed speed in inches/minute you need to move at to compare with the rates your mill feed provides.

If you are winding the handle manually you probably wan to convert it to inches per second so divide by 60, then multiply by the tpi of your leadscrew. Then you really get a feel of how fast it is and remember if you wobble in your turning you will get grabs or rubbing.

All this can be applied to vertical cutters too and remember not to climb mill on an old machine.

(now I'm off to find the manuals for my machine as I'm not sure I've been going as quick as I should)

ahhh, so the 0.004 is LENGTH of cut, not depth of cut. I think I get it now!

so if I had say 250rpm and a 20 tooth cutter, and I wanted cuts of 0.004, I’d need 20 ipm feed.

if my mill did 66 rpm and it’s designed to, with a 20 tooth cutter, and I wanted 0.004 cuts, I’d need 5.28 ipm feed.

But the fastest it can go is 3 ipm at 250rpm.

Something is not right about my mill!

Edited By Steve355 on 02/01/2022 15:00:25
2 January 2022 at 15:20 #578112
JasonB
Moderator
@jasonb
Posted by Steve355 on 02/01/2022 14:59:36:

But the fastest it can go is 3 ipm at 250rpm.

Something is not right about my mill!

You said the 3" was with it in the slowest speed of the feed pullies, what is it in the fastest?
3 January 2022 at 10:33 #578204
Steve355
Participant
@steve355
3” is with the pulley that gives 250rpm on the spindle

Obviously with the spindle running faster the feed will be quicker. But as I understand it I need the spindle running slower (say 120 rpm) and the feed running faster, or at least the same.

Right now it’s like this, with the motor pulley being the small pulley and the large pulley being the driver for the countershaft… this gives 250rpm at the spindle.

Perhaps the easiest/cheapest way to fix it is to increase the size of the countershaft pulley…

Which would give 125 rpm ish at the spindle, a lot closer to the ballpark needed. But the feed would be 1.5 ipm.

I saw an advert for later versions of the mill, which had a hydraulic system for feeding the table. Perhaps that was a solution to the inherent difficulty of having a suitable feed rate and low spindle speed.

thoughts appreciated 🥺

Edited By Steve355 on 03/01/2022 10:40:18
3 January 2022 at 10:49 #578208
Dave S
Participant
@daves59043
How is the feed taken off?

Could you change the spindle pulley and a subsequent feed pulley to give a more appropriate ratio?

Dave
3 January 2022 at 11:25 #578217
Steve355
Participant
@steve355
Posted by Dave S on 03/01/2022 10:49:20:

How is the feed taken off?

Could you change the spindle pulley and a subsequent feed pulley to give a more appropriate ratio?

Dave

I don’t think so, the feed pulley for the spindle is about as small as it can be and the spindle pulley is about as big as it can reasonably be. See pic below.

I feel a vfd coming on, wallet is getting worried.

Edited By JasonB on 03/01/2022 13:27:46
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